Compare the triplets | Hackerrank Problems

Alice and Bob each created one problem for HackerRank. A reviewer rates the two challenges, awarding points on a scale from 1 to 100 for three categories: problem clarity, originality, and difficulty.

The rating for Alice’s challenge is the triplet a = (a[0], a[1], a[2]), and the rating for Bob’s challenge is the triplet b = (b[0], b[1], b[2]).

The task is to find their comparison points by comparing a[0] with b[0], a[1] with b[1], and a[2] with b[2].

If a[i] > b[i], then Alice is awarded 1 point.
If a[i] < b[i], then Bob is awarded 1 point.
If a[i] = b[i], then neither person receives a point.

Comparison points is the total points a person earned.

Given a and b, determine their respective comparison points.

Example

a = [1, 2, 3]
b = [3, 2, 1]

For elements *0*, Bob is awarded a point because a[0] .
For the equal elements a[1] and b[1], no points are earned.
Finally, for elements 2, a[2] > b[2] so Alice receives a point.

The return array is [1, 1] with Alice’s score first and Bob’s second.

Function Description

Complete the function compareTriplets in the editor below.

compareTriplets has the following parameter(s):

int a[3]: Alice’s challenge rating
int b[3]: Bob’s challenge rating

Return

int[2]: Alice’s score is in the first position, and Bob’s score is in the second.

Input Format

The first line contains 3 space-separated integers, a[0], a[1], and a[2], the respective values in triplet a.
The second line contains 3 space-separated integers, b[0], b[1], and b[2], the respective values in triplet b.

Constraints

1 ≤ a[i] ≤ 100
1 ≤ b[i] ≤ 100

Sample Input 0

5 6 7
3 6 10

Sample Output 0

1 1

Explanation 0

In this example:

Alice’s comparison score is , and Bob’s comparison score is . Thus, we return the array .

Sample Input 1

17 28 30
99 16 8

Sample Output 1

2 1

Explanation 1

Comparing the 0th elements, 17<99 so Bob receives a point. Comparing the 1st and 2nd elements28>16, and 30>8 so Alice receives two points. The return array is [2,1]

Implementation

def compareTriplets(a, b):
    # Write your code here
    A=0
    B=0
    for i in range(0,len(a)):
        if a[i]>b[i]:
            A=A+1
        elif a[i]<b[i]:
            B=B+1
        else:
            continue
    return [A,B]

Above problem can also be solved by unzipping the scores array of alice and bob

def compareTriplets(a, b):
    alice_points = 0
    bob_points = 0

    for alice_score, bob_score in zip(a, b):
        if alice_score > bob_score:
            alice_points += 1
        elif alice_score < bob_score:
            bob_points += 1

    return alice_points, bob_points