HackerRank – DataStructure – Arrays

HackerRank Solution of Data Structure .Most of the question solution in c++ .I Will Try to Post very Question Solution that will help you to improve coding skill.For any query you can Ask me.

HackerRank Solution Arrays – DS in C

#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <assert.h>
#include <limits.h>
#include <stdbool.h>

int main()
{
    int n; 
    scanf("%d",&n);
    int *arr = malloc(sizeof(int) * n);
    for(int arr_i = 0; arr_i < n; arr_i++)
       scanf("%d",&arr[arr_i]);
    for(int arr_i = n-1; arr_i >=0; arr_i--)
        printf("%d ",arr[arr_i]);
    return 0;
}

HackerRank Solution 2D Array – DS in C

#include <assert.h>
#include <limits.h>
#include <math.h>
#include <stdbool.h>
#include <stddef.h>
#include <stdint.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char* readline();
char** split_string(char*);

// Complete the hourglassSum function below.
int hourglassSum(int arr_rows, int arr_columns, int** arr) 
{

    int i,j,sum,max=-500;
    for(i=1;i<5;i++)
    {
        sum=0;
        for(j=1;j<5;j++)
        {
            sum= arr[i-1][j-1]+arr[i-1][j]+arr[i-1][j+1]+arr[i][j]+arr[i+1][j-1]+arr[i+1][j]+arr[i+1][j+1];
            if(sum>max)
                max=sum;
        }
    }
    return max;
    
    

}

int main()
{
    FILE* fptr = fopen(getenv("OUTPUT_PATH"), "w");

    int** arr = malloc(6 * sizeof(int*));

    for (int i = 0; i < 6; i++) {
        *(arr + i) = malloc(6 * (sizeof(int)));

        char** arr_item_temp = split_string(readline());

        for (int j = 0; j < 6; j++) {
            char* arr_item_endptr;
            char* arr_item_str = *(arr_item_temp + j);
            int arr_item = strtol(arr_item_str, &arr_item_endptr, 10);

            if (arr_item_endptr == arr_item_str || *arr_item_endptr != '\0') { exit(EXIT_FAILURE); }

            *(*(arr + i) + j) = arr_item;
        }
    }

    int arr_rows = 6;
    int arr_columns = 6;

    int result = hourglassSum(arr_rows, arr_columns, arr);

    fprintf(fptr, "%d\n", result);

    fclose(fptr);

    return 0;
}

char* readline() {
    size_t alloc_length = 1024;
    size_t data_length = 0;
    char* data = malloc(alloc_length);

    while (true) {
        char* cursor = data + data_length;
        char* line = fgets(cursor, alloc_length - data_length, stdin);

        if (!line) { break; }

        data_length += strlen(cursor);

        if (data_length < alloc_length - 1 || data[data_length - 1] == '\n') { break; }

        size_t new_length = alloc_length << 1;
        data = realloc(data, new_length);

        if (!data) { break; }

        alloc_length = new_length;
    }

    if (data[data_length - 1] == '\n') {
        data[data_length - 1] = '\0';
    }

    data = realloc(data, data_length);

    return data;
}

char** split_string(char* str) {
    char** splits = NULL;
    char* token = strtok(str, " ");

    int spaces = 0;

    while (token) {
        splits = realloc(splits, sizeof(char*) * ++spaces);
        if (!splits) {
            return splits;
        }

        splits[spaces - 1] = token;

        token = strtok(NULL, " ");
    }

    return splits;
}

HackerRank Solution Left Rotation Array – DS in C++

#include <bits/stdc++.h>

using namespace std;

vector<string> split_string(string);



int main()
{
    string nd_temp;
    getline(cin, nd_temp);

    vector<string> nd = split_string(nd_temp);

    int n = stoi(nd[0]);

    int d = stoi(nd[1]);

    string a_temp_temp;
    getline(cin, a_temp_temp);

    vector<string> a_temp = split_string(a_temp_temp);

    vector<int> a(n);

    for (int i = 0; i < n; i++) {
        int a_item = stoi(a_temp[i]);

        a[i] = a_item;
    }
    vector <int> b(n);
    for(int i=0;i<n;i++)
        cout<<a[(i+d)%n]<<" ";
    
    
    
    
    
    return 0;
}

vector<string> split_string(string input_string) {
    string::iterator new_end = unique(input_string.begin(), input_string.end(), [] (const char &x, const char &y) {
        return x == y and x == ' ';
    });

    input_string.erase(new_end, input_string.end());

    while (input_string[input_string.length() - 1] == ' ') {
        input_string.pop_back();
    }

    vector<string> splits;
    char delimiter = ' ';

    size_t i = 0;
    size_t pos = input_string.find(delimiter);

    while (pos != string::npos) {
        splits.push_back(input_string.substr(i, pos - i));

        i = pos + 1;
        pos = input_string.find(delimiter, i);
    }

    splits.push_back(input_string.substr(i, min(pos, input_string.length()) - i + 1));

    return splits;
}

HackerRank Solution Sparse Arrays – DS

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

    public static void main(String[] args) 
    {
           Scanner sc=new Scanner(System.in);
           int n=sc.nextInt();
           String s[]=new String[n];
           for(int i=0;i<n;i++)
                s[i]=sc.next();    
           int a=sc.nextInt();
           String q[]=new String[a];
           for(int i=0;i<a;i++)
           {
               int x=0;
                q[i]=sc.next();
                for(int j=0;j<n;j++)
                {
                    if(s[j].equals(q[i]))
                        x++;
                }
                System.out.println(x);
    }
  }
}

HackerRank Solution Array Manipulation – DS

#include <bits/stdc++.h>

using namespace std;

vector<string> split_string(string);

// Complete the arrayManipulation function below.
long arrayManipulation(int n, vector<vector<int>> queries) 
{
    long max=LONG_MIN,sum=0;
    vector<long> a(n+1, 0);
    for(int i=0;i<queries.size();i++)
    {
        a[queries[i][0]]+=queries[i][2];
        if(queries[i][1]+1<=n)
            a[queries[i][1]+1]-=queries[i][2];
    }
    for(int i=1;i<=n;i++)
    {
        sum+=a[i];
        if(sum>max)
            max=sum;
    }
    return max;
}

int main()
{
    ofstream fout(getenv("OUTPUT_PATH"));

    string nm_temp;
    getline(cin, nm_temp);

    vector<string> nm = split_string(nm_temp);

    int n = stoi(nm[0]);

    int m = stoi(nm[1]);

    vector<vector<int>> queries(m);
    for (int i = 0; i < m; i++) {
        queries[i].resize(3);

        for (int j = 0; j < 3; j++) {
            cin >> queries[i][j];
        }

        cin.ignore(numeric_limits<streamsize>::max(), '\n');
    }

    long result = arrayManipulation(n, queries);

    fout << result << "\n";

    fout.close();

    return 0;
}

vector<string> split_string(string input_string) {
    string::iterator new_end = unique(input_string.begin(), input_string.end(), [] (const char &x, const char &y) {
        return x == y and x == ' ';
    });

    input_string.erase(new_end, input_string.end());

    while (input_string[input_string.length() - 1] == ' ') {
        input_string.pop_back();
    }

    vector<string> splits;
    char delimiter = ' ';

    size_t i = 0;
    size_t pos = input_string.find(delimiter);

    while (pos != string::npos) {
        splits.push_back(input_string.substr(i, pos - i));

        i = pos + 1;
        pos = input_string.find(delimiter, i);
    }

    splits.push_back(input_string.substr(i, min(pos, input_string.length()) - i + 1));

    return splits;
}

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